In case of carbon disulphide the bond formation involves the overlapping of the electrons from the 2p-subshell of carbon and 3p-subshell of Sulphur.

The lone pairs in case of Sulphur will be 2 . As there are 4 unpaired electrons as shown below.

And the hybridization of this will be sp³ hybrid

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google photo

You are commenting using your Google account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s

This site uses Akismet to reduce spam. Learn how your comment data is processed.