An organic compound of carbon, hydrogen and nitrogen contains elements having a mass percentage of 66.67%, 7.41% and 25.92%, respectively. What is the empirical formula?

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Step 1 : Assume the percentage as grams and divide it with molar mass.

Step 2: By this way you have calculated the number of moles , further divide evey term with the smallest term which you have calculated in step 1.

Step 3 : Now you have the simple whole number ratio of elements just put these numbers as subscripts on the lower side of the symbols of elements and u will get the empirical formula.

Solution:

66.67/12 =5.555 moles of C

7.41/1 =7.41 moles of H

25.92/14 =1.851 moles of N

Now

5.555/1.851= 3.001 for C

7.41/1.851= 4.005 for H

1.851/1.851=1 for N

So the empirical formula will be C3H4N .

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