Answer :-
In case of BCC (body centred cubic) structure coordination number is 8
exact answers only
In case of ferromagnetic substaces the direction of domains align themselves in the direction of external magnetic field appllied . This leads to the formation of strong magnetic field. This magnetic field persists even on removing the external magnetic field. so the ferromagnmetic substances can be used for making the permanent magnet.
on supply of heat the lattice particles absorb energy and leave the lattice this may lead to the vacancy defect. In this case the density of the lattice decrease as the particles permanently leave the lattice. The lattice may become coloured .
Solution:-
The number of N atoms in CCP (fcc) = 4 per unit cell
Number of tetrahedral voids = 2 x number of atoms
= 2 x 4
= 8
Atoms of element M occupy 1/3 rd of tetrahedral voids of tetrahedral voids, so
number of M atoms = 8 x 1/3
ratio of M and N = 8/3 : 4
= 2 : 3
formula of the compound = M2 N3
(i) At corner :- The particle present at the corner is shared by eight unit cells . hence 1/8 part of the particle is the share of a single unit cell.
(ii) At the body centre :- In case of body centre , the particle is present exactly at the centre of unit cell. hence it is not shared with any other unit cell , thus it belongs to the unit cell as 1 complete particle.
In case of face centred unit cell the particles are present on the corners of the unit cell as well as on the centre of every face.
In case of end centred unit cell the particles are present on the corners as well as on the centres of any two opposite faces.
In case of ionic solids , the ions are the units for the conduction of electricity. when they are in solid state the ions are bound to each other by strong electrostatic forces of attraction . But in the molten form the ions are free to move under the applied electric field thus they can conduct the electricity in molten form.
The solid which has same value for refractive index in all directions , shows isotropic behaviour and such solids are only the amorphus solids.
As it is an amorphus solid so it will not show the clean cut due to the presence of rough surface.
In case of carboxylic acids the OH bond is more polar due to the presence of carbonyl group.
The C=O group attracts more electrons towards itself which makes the -OH more polar. Due to higher polarity the magnitude of H-bonding also increase considerably in case of carboxylic acids as compared to alcohols. So the boiling point of carboxylic acids also increase.