Chemistry

Why are pantahalides more covalent than trihalides?

It can be easily learned by Fazan’s rule that ion with more charge/radius ratio has more polarizing power. Now in case of pentahalides +5 , the charge/radius ratio is higher than +3, thus pentahalides have more polarizing power , thus it shows covalent character.

How the alkaline medium prevents the rusting of iron ?

The Rate of rusting of iron depends upon the availability of H+ ions , more the ions more will be the rusting. But if we provide the alkaline medium  , it will decrease the concentration of H+ ions. Thus the iron will not be oxidized from Fe to Fe2+ .

What is chemical equilibrium ?

In case of reversible reactions , if the products are allowed to stand undisturbed then they start the backward reaction. This process happens until we get 1:1 of products and reactants. The whole phenomenon is called chemical equilibrium.

Why is molality preferred over the molarity ?

In case of molarity the volume of solvent is taken but in case of molality the mass of solvent is taken. With change in temprature the volume can increase or decrease but the mass remains same . So molality is preferred over the molarity. The main reason for this is that the molarity is the

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Why halogens are coloured ?

In case of halogens the electrons present in outer shell absorb the energy in visible region and get excited to higher level . During these transitions the emissions are in visible region thus these compounds appear coloured.

what are emulsions ? write two examples of emulsification.

Emulsion is the type of colliodal mixture :- In which the dispersion medium is oil and dispersed phase is water. for example ‘Butter’ In which the dispersion medium is water and dispersed phase is oil. for example ‘milk’ . Applications or examples of emulsification In case of cleaning action of soap, the soap solution acts

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A 0.1539 molal aqueous solution of cane sugar (molar mass = 342g )  has a freezing point of 271K while the freezing point of pure water is 273.15K . what will be the freezing point of an aqueous solution containing 5g of glucose (molar mass= 180g) per 100 g of solution?

Molality of the given solution = 0.1539m ∆Tf = 273.15 – 271 = 2.15 K Therefore ∆Tf  = Kf .m Kf = ∆Tf / m Kf = 2.15/0.1539  Now mass of the solute W2 = 5g Molar mass of the solute M2 = 180g Mass of the solution W1 = 100g  Now the mass of

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An antifreeze solution is prepared from 222.6 g of ethylene glycol C2H4(OH)2 and 200g of water . Calculate the molality of the solution . If the density of the solution is 1.072 g per / ml -1 , then what shall be the molarity of the solution ?

Solution:- Mass of ethylene glycol (solute) = 222.6 g Molar mass of ethylene glycol ( C2H4(OH)2 = 62g Number of moles of the solute = 222.6 / 62  = 3.59 moles Mass of the solvent (water) in solution = 200g = 0.200Kg Volume of the solution = 422.6 / 1.072 = 394.2 ml                                                 =

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Hi, I’m Ankush Sharma. post graduate in chemistry and organic chemistry specialist

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