In this method the methyl ketone is treated firstly with sodium hydroxide so we get the sodium salt of acid which is further treated with hydrochloric acid to get the final product , that is a carboxylic acid.
The strength of an acid depends upon the oxidation state of the central atom. More is the oxidation state higher is the acidic character. In case of HClO4(perchloric acid) the oxidation state of chlorine is +7. And in case of H2SO4 (sulphuric acid) the oxidation state of Sulphur is +6 . The oxidation state of
Meaning of diprotic acid is that , it can loose two hydronium ions (H+) . For finding how many H+ ions it can give , we have to see its structure. Here it have only two hydroxyl groups that is -OH groups, and the hydrogen atoms joined to these only are ionisable. So only these
Ald + ol Ald- Aldehyde ; ol – Alcohol. As the name suggests , this is a type of reaction which involve the formation of such a molecule which have “alcohol and aldehyde” functional groups.
There is a trick in learning this reaction I will make it very easy for you to learn and rewrite. Firstly see the reaction:- Na2CO3 + 2HCl → 2NaCl + CO2 + H2O Tricks to learn:– Firstly see the formula of carbonate its CO3 , this will be converted into CO2 , One oxygen of
In case of methanoic acid the carbon atom joined to the carboxyl group is attached to only hydrogen atoms which are not able to increase the electron density. HCOOH But in case of ethanoic acid we have a methyl group attached to the carbon of carboxyl group , which is electron releasing group and it
sulfuric acid ionizes to give us hydronium ion and sulfate ion. H2SO4 (aq) → 2H+ + SO4
The reaction between an acid and base to give salt and water is called neutralisation reaction. here in the following reaction we can easily see how Hydrochloric acid is reacting with sodium chloride NaOH + HCl ———> NaCl + H2O the nature of salt formed is dependent on the type of acid or base , if