In case of transition metals the Manganese exhibit large range of oxidation state from +2 to +7. This is due to the fact that it has the highest number of unpaired electrons in its outer shell. The configuration of Mn is [Ar] 3d5 4s2 thius it can use its 7 electrons to show the large
It is the amount of lyophilic sol required in milligrams to prevent the the coagulation of 10ml gold sol by the addition of 1 ml, 10% NaCl solution .
The answer to this question is very simple . There are two major reasons behind it. 1. Catenation :- It is the property by which the carbon can make long chains, branched chains and ring or cylic structural by joining with its own atoms. Due to this it can make a variety of molecules. 2.
It is the reaction between alkyl halides and sodium in the dry ether to give alkanes with higher number of carbon. 2R-X + 2 Na —> R-R +2NaX
It is the number of lattice points touching one lattice point in a crystalline solid. For example in case of Sodium chloride it is 6 .
1. Co-ordination number Number of spheres touching one Sphere in a close packed structure is called co-ordination number of a lattice 2. Unit cell The smallest repeating pattern in a crystal lattice is called a unit cell. Characteristics of unit cell Are unit cell has a characteristic dimensions along the three edges a,b,c and interfacial
For calculation of number of atoms we have to calculate the number of moles present in 1gram carbon. Multiply the number of moles with Avogadro number. Step I Number of moles in 1 gram of carbon = given mass / molar mass Molar mass (molecular or atomic mass expressed in grams) = 12g So the
1 molecule of H2O has 1 atom of oxygen. Firstly we will calculate the number of atoms in 90g of H2O. we will explain it in two steps:- Step I:- No.of moles of H2O = given mass / molar mass No. of moles = 90/18 = 5 moles No. Of molecules = No. of moles
Here we have 126 AMU of HNO3, Molar mass of HNO3 is 1+14+16×3 = 63amu Number of molecules of HNO3 are = 126/63 = 2 Here we have 2 molecules Each molecule have 3 atoms of oxygen. So no. of oxygen atoms= 3×2 =6 atoms No. Of moles = given particles/ avogadro number No. of