How in copper sulphate electrolysis with copper metal (electrode) the number of Cu+2 ions oxidised are to the one reduced?

in this case one of the electrode is of copper, and this copper electrode is taken as anode. so the oxidation takes place here.

The half reaction taking place on anode – Oxidation

Cu → Cu2+   +   2e

Similarly on cathode side reduction takes place as follows

Cu2+   +   2e   →  Cu

Published by ankushmaster

I am M.Sc (chemistry ) from punjabi university. I am a science teacher with expertise in chemistry, with 8 years of experiance in teaching. i am getting a handsome salary , now i wish to help out the people who need me UNCONDITIONALLY. and I am constantly working on creating a new and easy way of learning the tough things in an effective way. I am constantly working to make authentic and reliable information to be shared with my students and widen the horizons of knowledge.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s

This site uses Akismet to reduce spam. Learn how your comment data is processed.

%d bloggers like this: