How in copper sulphate electrolysis with copper metal (electrode) the number of Cu+2 ions oxidised are to the one reduced?

in this case one of the electrode is of copper, and this copper electrode is taken as anode. so the oxidation takes place here.

The half reaction taking place on anode – Oxidation

Cu → Cu2+   +   2e

Similarly on cathode side reduction takes place as follows

Cu2+   +   2e   →  Cu

Published by Ankush Sharma

I am M.Sc (chemistry ) from Punjabi University Patiala. I am a science teacher with expertise in chemistry, with 8 years of experience in teaching. Writing and blogging is my hobby, I write whenever I am free. I am constantly working on creating a new and easy way of learning the tough things in an effective way. I am constantly working to make authentic and reliable information to be shared with my students and widen the horizons of knowledge.

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