An organic compound of carbon, hydrogen and nitrogen contains elements having a mass percentage of 66.67%, 7.41% and 25.92%, respectively. What is the empirical formula?

Step 1 : Assume the percentage as grams and divide it with molar mass.

Step 2: By this way you have calculated the number of moles , further divide evey term with the smallest term which you have calculated in step 1.

Step 3 : Now you have the simple whole number ratio of elements just put these numbers as subscripts on the lower side of the symbols of elements and u will get the empirical formula.


66.67/12 =5.555 moles of C

7.41/1 =7.41 moles of H

25.92/14 =1.851 moles of N


5.555/1.851= 3.001 for C

7.41/1.851= 4.005 for H

1.851/1.851=1 for N

So the empirical formula will be C3H4N .

Published by ankushmaster

I am M.Sc (chemistry ) from punjabi university. I am a science teacher with expertise in chemistry, with 8 years of experiance in teaching. i am getting a handsome salary , now i wish to help out the people who need me UNCONDITIONALLY. and I am constantly working on creating a new and easy way of learning the tough things in an effective way. I am constantly working to make authentic and reliable information to be shared with my students and widen the horizons of knowledge.

Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s

This site uses Akismet to reduce spam. Learn how your comment data is processed.

%d bloggers like this: