Mechanism of substitution reactions of Alkanes

This kind of reactions involve the formation of free radical intermediates. Following are the steps of mechanism :-

Step 1 :- Chain initiation

In this step the bond in halide molecule breaks by a homolytic cleavage . And this leads to the formation of free radicals.

Step 2 :- Chain propagation

In this step the free radicals attack on the alkane and remove the hydrogen. This leads to the formation of carbon free radical.

Step 3 :- Chain termination

In this step the free radicals formed during the reaction are consumed in the various possible combinations as shown below.

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