Mechanism of substitution reactions of Alkanes

One comment

This kind of reactions involve the formation of free radical intermediates. Following are the steps of mechanism :-

Step 1 :- Chain initiation

In this step the bond in halide molecule breaks by a homolytic cleavage . And this leads to the formation of free radicals.

Step 2 :- Chain propagation

In this step the free radicals attack on the alkane and remove the hydrogen. This leads to the formation of carbon free radical.

Step 3 :- Chain termination

In this step the free radicals formed during the reaction are consumed in the various possible combinations as shown below.

1 comments on “Mechanism of substitution reactions of Alkanes”

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s

This site uses Akismet to reduce spam. Learn how your comment data is processed.