The number of N atoms in CCP (fcc) = 4 per unit cell
Number of tetrahedral voids = 2 x number of atoms
= 2 x 4
Atoms of element M occupy 1/3 rd of tetrahedral voids of tetrahedral voids, so
number of M atoms = 8 x 1/3
ratio of M and N = 8/3 : 4
= 2 : 3
formula of the compound = M2 N3
Published by Ankush Sharma
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